4NH3(g) + 6NO(g)→5N2(g) + 6H2O(g) How many moles of each reactant were there if 13.7 moles of N2(g) is produced?

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4NH3(g) + 6NO(g)→5N2(g) + 6H2O(g)

How many moles of each reactant were there if 13.7 moles of N2(g) is produced?

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